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## Homework Statement

[PLAIN]http://img220.imageshack.us/img220/2589/44045733.png [Broken]

Semicircular wire MN of diameter L moves with speed v perpendicularly through a uniform magnetic field of strength B.

1. Find the magnitude of the induced emf generated between M and N.

2. State whether M or N is at a higher potential.

## Homework Equations

E = BLv

## The Attempt at a Solution

__1. Given answer: Induced emf = BLv__

However, I was wondering if you can use that equation even if it's not a closed circuit?

In the semicircular wire, there shouldn't be magnetic flux linkage. And even if there was, there is no change in magnetic flux linkage.

__2. N is at a higher potential__

There is opposing force that resists the motion of the wire ( is this reason correct?), which, by Fleming's left hand rule, results in an induced current (if the circuit were to be closed) flowing from M to N. Thus, N is at higher potential as a result of the induced "current".

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?

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