Relationship between valence electrons and electron configuration

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SUMMARY

The discussion centers on the stability of atoms in relation to their valence electrons and electron configurations. It is established that atoms typically achieve stability with eight valence electrons, a concept known as the octet rule, which is evident in the electron configurations of noble gases like Neon (1s² 2s² 2p⁶). The conversation also addresses the stability of alkali Earth metals, which fill the 2s orbital but do not achieve octet stability. The role of electronegativity and the influence of electron configurations on atomic stability are critically examined, concluding that not all atoms require eight valence electrons for stability.

PREREQUISITES
  • Understanding of the octet rule in chemistry
  • Familiarity with electron configurations, particularly for noble gases
  • Knowledge of electronegativity and its effects on atomic stability
  • Basic concepts of atomic structure and orbitals
NEXT STEPS
  • Research the octet rule and its exceptions in chemical bonding
  • Study the electron configurations of various elements beyond noble gases
  • Explore the concept of electronegativity and its role in chemical reactions
  • Investigate the stability of transition metals and their electron configurations
USEFUL FOR

Chemistry students, educators, and anyone interested in atomic structure and chemical bonding principles.

Rulesby
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Why is it that atoms must have 8 valence electrons in order to be stable?

Aren't electrons most stable when the orbital is completely filled? Helium's electron configuration is 1s^2, Neon's is 1s^2 2s^2 2p^6, etc. All the noble gases, except for helium, have the p orbital filled.

I'm wondering why the p orbital has to be filled in order for the configuration to be stable. Why, for example, aren't the alkali Earth metals stable since they all fill the 2s orbital.

Is it because the electronegativity is too weak? If so, why doesn't boron or carbon tend to form give only 1 electron in boron's case or 2 electrons in carbon's case in order to empty the p orbital and be satisfied with a filled 2s orbital? Surely they have enough electronegativity to hold on to the electrons in the 2s orbital.

Of course, empirical data can tell you that the atom likes to have 8 valence electrons, but my idea of the electron configurations doesn't reflect that, so I probably have the wrong idea.

So what forces are responsible for influencing an atom to have 8 valence electrons, and how does the electron configuration agree with this?
 
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Rulesby said:
Why is it that atoms must have 8 valence electrons in order to be stable?

Aren't electrons most stable when the orbital is completely filled? Helium's electron configuration is 1s^2, Neon's is 1s^2 2s^2 2p^6, etc. All the noble gases, except for helium, have the p orbital filled.

I'm wondering why the p orbital has to be filled in order for the configuration to be stable. Why, for example, aren't the alkali Earth metals stable since they all fill the 2s orbital.

Is it because the electronegativity is too weak? If so, why doesn't boron or carbon tend to form give only 1 electron in boron's case or 2 electrons in carbon's case in order to empty the p orbital and be satisfied with a filled 2s orbital? Surely they have enough electronegativity to hold on to the electrons in the 2s orbital.

Of course, empirical data can tell you that the atom likes to have 8 valence electrons, but my idea of the electron configurations doesn't reflect that, so I probably have the wrong idea.

So what forces are responsible for influencing an atom to have 8 valence electrons, and how does the electron configuration agree with this?

Not all atoms must have 8 valence electrons in order to be stable.
 

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