Relative Extension of Collagen Fiber: %0.8

[edorf]

1. Collagen fiber is stressed with 12 N force. The cross-sectional area of the fiber is 3 mm2, its coefficient of elasticity is 500 MPa. Give the percentage of relative extension.

I think i have found the correct equation but i can't seem to find the rigth answer which is suposed to be 0.8% but i always end up with 8*10^-4..

Homework Equations

F/A=E Δl/l

The Attempt at a Solution

12N/(0,003m^2 * 5*10^6 Pa)

and then I get a result of 8*10^-4, and I am stuck.. I believe there is something fundamental I have missed but I can't seem to find it.. Thanks in advance!

 

[tiny-tim]

welcome to pf!

hi edorf! welcome to pf!

(try using the X² tag just above the Reply box )

The cross-sectional area of the fiber is 3 mm2, its coefficient of elasticity is 500 MPa. Give the percentage of relative extension.
…
12N/(0,003m^2 * 5*10^6 Pa)

erm … 3 mm² isn't .003 m², is it?

(and you left the 00 out of 500)

 

[edorf]

ahhhhh...! Thank you so much!:D I guess that's what happends when you try to solve problems for 8h straight :P