- #1

canucklehead

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## Homework Statement

A plane attains an airspeed of 620 km/hr. The plane sets out for a destination 1085 km to the north (a 0° course) but discovers that the plane must be headed 20° east of north to fly there directly. The plane arrives in 2.00 h.

What is the wind speed?

What is the direction of the wind?

## Homework Equations

Vf = Vi + a*t

x = vi*t + 0.5a*t^2

vf^2 = vi^2 + 2a*x

V in x-dir'n = |Vi|cosΘ

V in y-dir'n = |Vi|sinΘ

## The Attempt at a Solution

I found the north component of velocity as 1850km/2.00h = 542.5km/h

But after that I am completely lost.

Then, I think to find the direction of the wind u need inverse-tan of the y-dir'n velocity & x-dir'n velocity of the wind? But I can't do that without getting the first part first.

Please, help. Thx.

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