1. The problem statement, all variables and given/known data A plane attains an airspeed of 620 km/hr. The plane sets out for a destination 1085 km to the north (a 0° course) but discovers that the plane must be headed 20° east of north to fly there directly. The plane arrives in 2.00 h. What is the wind speed? What is the direction of the wind? 2. Relevant equations Vf = Vi + a*t x = vi*t + 0.5a*t^2 vf^2 = vi^2 + 2a*x V in x-dir'n = |Vi|cosΘ V in y-dir'n = |Vi|sinΘ 3. The attempt at a solution I found the north component of velocity as 1850km/2.00h = 542.5km/h But after that I am completely lost. Then, I think to find the direction of the wind u need inverse-tan of the y-dir'n velocity & x-dir'n velocity of the wind??? But I can't do that without getting the first part first. Please, help. Thx.