Relativistic Momentum to Kinetic Energy Conversion

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Discussion Overview

The discussion revolves around the conversion of relativistic momentum to kinetic energy during a collision involving a massive object traveling at near-light speed. Participants explore the implications of relativistic mass, momentum transfer, and energy conservation in the context of high-velocity impacts.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant describes a scenario involving a massive object, like a neutron star, colliding with a static object and questions how relativistic mass converts to kinetic energy during the impact.
  • Another participant challenges the notion that momentum is dissipated "exponentially" during deceleration and asks for clarification on this claim.
  • A participant asserts that as the dynamic object loses velocity, its relativistic mass decreases, which raises questions about the transfer of momentum during the collision.
  • There is a discussion about whether Newtonian mechanics applies at relativistic speeds, with some participants suggesting that momentum is still transferred despite the complexities introduced by relativity.
  • One participant expresses confusion about the apparent loss of energy during the collision, noting that energy must be conserved, which leads to further exploration of how relativistic mass and momentum interact.
  • Mathematical expressions for momentum in both non-relativistic and relativistic contexts are provided, indicating that the definition of mass plays a role in understanding momentum transfer.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the specifics of how relativistic momentum is converted to kinetic energy or the implications of relativistic mass on momentum transfer. Multiple competing views remain regarding the application of Newtonian mechanics at relativistic speeds and the nature of energy conservation in such scenarios.

Contextual Notes

Participants express uncertainty about the implications of relativistic effects on momentum and energy transfer, and there are unresolved questions about the mathematical treatment of these concepts.

mayeraus41
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Just consider the following;
A large object, say a sun or neutron star, is traveling through the universe at near the speed of light (let's say 99% of c). This super massive object is on a collision course with a fixed/static super massive object relative to the body in motion. When the eminent impact occurs, the dynamic object will transfer it's momentum to the static body, Newtons third law, almost like astronomical scale Newton balls. The problem is, how is the relativistic mass converted into kinetic energy, assuming that the transfer is not instantaneous and occurs over a span of time. To me it would seem as though energy potential is lost all together as it decelerates because the relativistic mass is not transferred as it dissipates exponentially while the force is not transferred exponentially.

If someone could please help explain how the relativistic momentum/mass is converted to kinetic energy that would alleviate the spitting psyche headache. I know I'm wrong because energy must be conserved, but would like someone to explain how.

Thanks.
 
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This seems to be the crux of your argument:
mayeraus41 said:
...energy potential is lost all together as it decelerates because the relativistic mass is not transferred as it dissipates exponentially...
Why do you say the [momentum] is dissipated "exponentially"?
 
Because the dynamic object is losing velocity, at least in the incipient stage of impact. And if I know my relativity equations I know that as velocity decreases, Mass does proportionally.
 
mayeraus41 said:
Because the dynamic object is losing velocity, at least in the incipient stage of impact. And if I know my relativity equations I know that as velocity decreases, Mass does proportionally.

Ah I see. The object's relativistic mass drops as it slows.

But why do you think the momentum is not being transferred?

You don't measure mass alone in the collision, you measure momentum. That's what gets transferred. The momentum of the object takes into account its relativistic velocity.
 
DaveC426913 said:
Ah I see. The object's relativistic mass drops as it slows.

But why do you think the momentum is not being transferred?

You don't measure mass alone in the collision, you measure momentum. That's what gets transferred. The momentum of the object takes into account its relativistic velocity.

So are you saying that standard Newtonian understanding of momentum doesn't or does apply at relativistic velocity? If not how is the relativity factored into momentum? That's a bit off topic but still I'm curious.

My thought is that through the collision speed is lost or at least distributed across the two objects to a level below any significant relativistic speed. therefore momentum is lost.
 
mayeraus41 said:
So are you saying that standard Newtonian understanding of momentum doesn't or does apply at relativistic velocity?
The momentum is transferred. How the object gets the momentum it does (whether via its rest mass or its velocity or its relativistic mass) seems to be immaterial.

I confess, I do not have a concise answer, I am just following the logic.
 
DaveC426913 said:
The momentum is transferred

I confess, I do not have a concise answer, I am just following the logic.

Irrelevant as it may be, still fascinating to consider. It's difficult for me to quantify as energy is required to attain the relativistic mass and higher velocity. To me the energy almost disapears. And I know that to be impossible, that's why i find it troubling.
 
mayeraus41 said:
So are you saying that standard Newtonian understanding of momentum doesn't or does apply at relativistic velocity? If not how is the relativity factored into momentum?

In non-relativistic mechanics, p = mv. In relativistic mechanics,

p = \frac {mv} {\sqrt {1 - v^2 / c^2}}

where m in both cases is the "invariant mass" of relativity.

If you prefer to think in terms of what is often called "relativistic mass" (but is not commonly used by physicists nowadays) then p = mv in both cases, and relativity factors into the definition of "relativistic mass."
 

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