Relativity and Lorentz Transformations

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SUMMARY

The discussion focuses on the application of Lorentz transformations to analyze the scenario of two spaceships, A and B, with A traveling at 0.6c. The key calculations involve determining the time readings on the clocks of both spaceships when a light flash emitted from A reaches its rear and subsequently is observed from B. The proper length of spaceship A is 30m, and the calculations yield a time reading of 5.0 x 10-8 seconds on spaceship B's clock when the light reaches the rear of spaceship A.

PREREQUISITES
  • Understanding of Lorentz transformation formulas
  • Knowledge of proper length in special relativity
  • Familiarity with the concept of time dilation
  • Basic principles of light propagation in a vacuum
NEXT STEPS
  • Study the derivation of Lorentz transformation equations
  • Explore the implications of time dilation in different reference frames
  • Learn about the concept of simultaneity in special relativity
  • Investigate practical applications of Lorentz transformations in physics
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Physics students, educators, and anyone interested in understanding the principles of special relativity and Lorentz transformations in the context of high-speed travel.

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Homework Statement


Spaceship A of length 30m travels at 0.6c past spaceship B. Clocks in frame S' of spaceship A and S of spaceship B are synchronised within their respective frames of reference and are set to zero, so that t' = t = 0 at the instant the front of spaceship A passes the rear of spaceship B located at x' = x = 0. At this time a light flashes at the front of spaceship A.

a. When the light flash reaches the rear of spaceship A, what is the reading of a clock there?
b. What is the reading on the clock on spaceship B when according to an observer on B, the flash reaches the rear of A?

Homework Equations


Lorentz transformation formulas

The Attempt at a Solution


a. From spaceship A's POV, it is stationary. It measures proper length. Thus time t1' = 30m / speed of light. Is this correct?

b. Using Lorentz transformation of time,
t = γ(t' + ux'/c2)

x1' = -30, u = 0.6c and t1' from answer in a, I got t1 = 5.0*10-8 s. Does this work?

Thanks!
 
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little neutrino said:

Homework Statement


Spaceship A of length 30m travels at 0.6c past spaceship B. Clocks in frame S' of spaceship A and S of spaceship B are synchronised within their respective frames of reference and are set to zero, so that t' = t = 0 at the instant the front of spaceship A passes the rear of spaceship B located at x' = x = 0. At this time a light flashes at the front of spaceship A.

a. When the light flash reaches the rear of spaceship A, what is the reading of a clock there?
b. What is the reading on the clock on spaceship B when according to an observer on B, the flash reaches the rear of A?

Homework Equations


Lorentz transformation formulas

The Attempt at a Solution


a. From spaceship A's POV, it is stationary. It measures proper length. Thus time t1' = 30m / speed of light. Is this correct?

b. Using Lorentz transformation of time,
t = γ(t' + ux'/c2)

x1' = -30, u = 0.6c and t1' from answer in a, I got t1 = 5.0*10-8 s. Does this work?

Thanks!
Yes.
 
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