What is the Relativity of Velocities Formula?

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SUMMARY

The discussion centers on calculating the speed of two spaceships approaching each other, each moving at a speed that results in a relative speed of 0.89c as measured by an observer on Earth. The formula used is the relativistic velocity addition formula: u = (u' + v) / (1 + u'v/c²). The correct approach involves substituting the speeds appropriately, leading to the final speed of each spaceship as approximately 1.8326 x 108 m/s. The error in the initial approach was clarified, emphasizing the correct use of the formula for relative motion.

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Homework Statement


Two spaceships approach each other, each moving with the same speed as measured by an observer on the Earth. If their relative speed is 0.89c, what is the speed of each spaceship as measured on Earth?


Homework Equations


u=\frac{u'+v}{1+u'v/c^2}

3. My work
so ship A moves to the right at speed u, (according to an observer on earth)
and ship B moves to the left at speed v, (according to an observer on earth)
within Ship A's inertial frame, ship B is moving at u', known to be .89c
i need to solve for u, the speed on Ship A.
u=-v

substituting -v for u,
u= \frac{u&#039;-u}{1-u&#039;u/c<sup>2</sup>}

i then get
0=-\frac{u&#039;u<sup>2</sup>}{c<sup>2</sup>}+u

I am sure i am thinking of this problem the wrong way, maybe that v does not equal the negative of u?
 
Last edited:
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i accidently posted this before adding my work, ill get it on in a moment
 
Found my error.
since the ships are approaching each other, the equation was
u=\frac{v-u&#039;}{1-\frac{u&#039;v}{c^{2}}}

then substituting -v = u

\frac{u&#039;u^{2}}{c^{2}}+u'+2u=0

which yields the correct answer of 1.8326x108 m/s
 

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