# Removing heat energy from a block of ice

## Homework Statement

How much energy must be removed from a 4.50 cm x 4.30cm x 6.20cm block of ice to cool it from 0C to -31.0C?

The density of ice is 920 kg/m^3. You might need to refer to the textbook for other physical constants of ice.

## Homework Equations

Q = Mc(T_f-T_i)

heat energy = mass*heat capacity * change in temp

M = Density*volume

## The Attempt at a Solution

Q = Mc(T_f-T_i) = DVc(T_f-T_i)

Q = (920)(.045*.042*.062)(2180)(-31-0)= -7285.5 joules

Last edited:

kuruman
Homework Helper
Gold Member
Is there a question you wish to ask?

Are you saying that this is right?

kuruman
Homework Helper
Gold Member
I am asking you if you wish to ask a question because your original posting does not include one. If you do, please ask and I (we) will do my (our) best to answer it.

Don't you need to know how much heat you need to pull out of it? Doesn't the method I have listed do that? It finds the heat energy removed doesn't it?

kuruman
Homework Helper
Gold Member
Yes, yes and yes. However, if this is an answer that you need to put in a computerized homework system, you need to understand the sign conventions.

If the question asks to find "the heat that goes in" and the number is negative, that means that heat actually goes out. In this case, the question is to find the heat that goes out, therefore a positive number is in order.

So its just 7285.5 joules then?

kuruman