How much energy must be removed from a 4.50 cm x 4.30cm x 6.20cm block of ice to cool it from 0C to -31.0C?
The density of ice is 920 kg/m^3. You might need to refer to the textbook for other physical constants of ice.
Q = Mc(T_f-T_i)
heat energy = mass*heat capacity * change in temp
M = Density*volume
The Attempt at a Solution
Q = Mc(T_f-T_i) = DVc(T_f-T_i)
Q = (920)(.045*.042*.062)(2180)(-31-0)= -7285.5 joules