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## Homework Statement

How much energy must be removed from a 4.50 cm x 4.30cm x 6.20cm block of ice to cool it from 0C to -31.0C?

The density of ice is 920 kg/m^3. You might need to refer to the textbook for other physical constants of ice.

## Homework Equations

Q = Mc(T_f-T_i)

heat energy = mass*heat capacity * change in temp

M = Density*volume

## The Attempt at a Solution

Q = Mc(T_f-T_i) = DVc(T_f-T_i)

Q = (920)(.045*.042*.062)(2180)(-31-0)= -7285.5 joules

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