Repulsive force of protons against protons.

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The discussion centers on the challenge of calculating the repulsive force between protons in the nucleus, distinguishing it from the strong nuclear force that binds them. The user seeks to express this force in Newtons rather than Coulombs, emphasizing the need for a clearer understanding of the interactions at play. They propose a formula involving charge and distance, recalling the approximate constant value of 9x10^9. The conversation highlights the complexity of nuclear forces and the importance of accurately measuring these interactions. Understanding these forces could provide insights into why protons remain bound within the nucleus despite their repulsive nature.
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While researching for a problem that I wanted to solve i came upon the fact that there is no way to truly calculate the repulsive force of protons in the nucleus with other protons in the nucleus and how at what point it starts to be truly repulsive and not the "strong nuclear force" that binds nucli together. So what is the repulsive force of two same charged same sized objects in Newtons not coulumbs? This can be used to calculate the same thing but inside the nucleus to see why protons truly are bound together.









(This is not a homework question don't move or delete it again thank you)
 
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I'm THINK (don't quote me on this) the force =

charge1 * charge2 * 9x109 / distance2

measuring charge in coulombs, and distance in meters. 9x109 is what I remember the approximation of the constant is, but it might be different.
 
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