Residue of Dirac delta function?

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Discussion Overview

The discussion revolves around the concept of the residue of the Dirac delta function, particularly in the context of complex analysis and distributions. Participants explore various approaches to defining or understanding the residue, considering both theoretical and practical implications.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions whether the Dirac delta function has a residue, noting their limited understanding of distributions and the absence of a Laurent expansion.
  • Another participant suggests using functions that approximate the delta function, such as \(\frac{1}{\pi} \frac{\sin(\lambda x)}{x}\) as \(\lambda \to \infty\) or \(\sqrt{\frac{\alpha}{\pi}}e^{-\alpha x^2}\) as \(\alpha \to \infty\), and proposes finding the residue with respect to \(\lambda\) and taking the limit.
  • A third participant proposes extending the Dirac delta function to the complex plane and examining its poles as a potential method for understanding its residue.
  • A later reply reflects on the initial question, noting that a contour integral around a delta-function singularity results in zero, leading to the conclusion that the residue cannot be inferred from the contour integral due to the non-analytic nature of the delta function.

Areas of Agreement / Disagreement

Participants express differing views on the existence and definition of a residue for the Dirac delta function, with no consensus reached on the matter.

Contextual Notes

Limitations include the lack of a clear definition of residue in the context of distributions and the implications of the delta function's non-analytic nature on contour integrals.

FredMadison
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Does the Dirac delta have a residue? It seems like it might, but I don't know how to attack it, since I really know very little about distributions. For example, the Dirac delta does not have a Laurent-expansion, so how would you define its residue?
 
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Perhaps you could try using something that approaches a delta function like \frac{1}{\pi} \frac{sin(\lambda x)}{x} as \lambda \to \infty or maybe \sqrt{\frac{\alpha}{\pi}}e^{-\alpha x^2} as \alpha \to \infty

Perhaps you could find the residue w.r.t. \lambda and take the limit. Not sure, just something to maybe try.
 
Have you tried extending the Dirac delta to the complex plane and then examining its poles?
 
Thanks for your replies, I have not had time yet to look into this more. I still think it's an interesting question, but my original motivation for it has disappeared, since I realized that a contour integral around a delta-function singularity will give 0, by simply looking at the definition of the complex integral - the integrand is in this case zero everywhere on the contour. I got fooled by thinking that since there is a "spike" inside the contour that would mean that I would have to look at the residues. Since delta(z) is not analytic, nothing can be inferred about its residue from the contour integral.
 

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