Hi all, I'm new here, been havin' a good ol' tussle with this one. Has me frustrated because it seems pretty elementary. 1. The problem statement, all variables and given/known data The circuit diagram has been drawn out in the attachment The problem asks what is the current through the 20 ohm resistor. 2. Relevant equations Parallel: 1/Req=1/R1+1/R2+...1/RN Series: Req=R1+R2+...RN I=V/R 3. The attempt at a solution I've added the 10 and 5 ohm resistors to make 10/3 ohm to simplify that area of the diagram. I've also added the 20 and 5 ohm resistors on the bottom end of the diagram to make 25 ohm. Thus, adding these two equivalent resistances gives me 85/3. This leaves the resistor to the left of the battery. Adding that one to this value as per the series rule of equivalent resistances gives me 115/3. Using this equivalent resistance, I can find the total current, which comes out to be I=25/(115/3)=75/115=.652 A. From here, I am at a loss as to how to use this value to calculate the specific current at the 20 ohm resistor. Am I even using the proper voltage to calculate the total current? The correct answer to this problem is 227 mA. Thanks, any help would be appreciated.