- #1

Piglet1024

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**1. A metallic semi-spherical bowl is filled with salty water. A metallic ball is suspended at the center of the bowl, so that it is half submerged in the water. The outer radius of the ball is a, and the inner radius of the bowl is b. The conductivity of the water is [tex]\sigma[/tex]. Calculate the resistance between the ball and the bowl.**

**2. R=[tex]\frac{L}{\sigma A}[/tex]**

**3. So I thought that for A I could use the difference between the surface area of the bowl and the ball, but then I thought well what if I need to find the area of the cross sections because the original thought seemed too simplistic. L, I feel, is obviously (b-a) but I could be wrong. This is more of a conceptual question, but did I think of the correct method above or did I completely miss the point?**