Resistance: find the equivalent resistance.

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Homework Help Overview

The discussion revolves around finding the equivalent resistance of a circuit involving resistors in series and parallel configurations. Participants are exploring the methods to simplify the arrangement of resistors to determine the total resistance.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss identifying resistors that are in series or parallel and suggest starting with pairs of resistors for analysis. There are attempts to clarify how to simplify the circuit and questions about the relationships between resistors in different configurations.

Discussion Status

The discussion is ongoing, with some participants providing guidance on how to approach the problem by focusing on pairs of resistors. Multiple interpretations of the circuit configuration are being explored, and there is no explicit consensus yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also mention of specific resistor values in the context of calculations.

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Homework Statement



resistance.png


Homework Equations



Resistors in series (in a straight line) add. Like R + R = 2R.

And if in parallel, they inversely add.

1/R_total = 1/R1 + 1/R2

So, I have no idea how to "simplify" this.

Basically trying to find the total resistance.

Thanks.
 
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Start by identifying resistors which are in series or parallel. What do you find?
 
Resistors in series or parallel that could be in series or parallel with others resistors that could be in series and parallel...
 
Start with some pair of resistors that you can analyse without having to consider a third. That could be two in series with no other resistor connected to their junction, or two directly in parallel - i.e. that make a direct connection to each other at each end. Having found such pair, figure out what the effective resistance of the pair is and replace the pair by a single equivalent resistor. Repeat.
 
1) if R=1ohm

R eq= 2.5ohms

relation: (2R+R)x(2R+R) / (2R+R) + (2R+R) + R

2) inverse add last two R, answer will series add with the R in the line, u will eventually see only two R in parallel, then inverse add these last two to get your answer.
 

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