Resistance of a Wire Cube: Diagnol Faces

[hamzanaveed]

A wire is broken down into 12 pieces so that each piece is of resistance 1R. The pieces are joined together to form a cube. What would be the resistance at the diagnols of the 4 faces of the cube?

 

[tiny-tim]

welcome to pf!

hi hamzanaveed! welcome to pf!

What would be the resistance at the diagnols of the 4 faces of the cube?

i don't understand what you mean (and also a cube has 6 faces)

anyway, show us what you've tried, and where you're stuck, and then we'll know how to help! ​

 

[yoshtov]

I am assuming you mean the resistance at two diagonal vertices of the cube. Try plotting out all of the different paths that current can take from point A to point B, and then go from there. see if you can put it in the form of a circuit diagram. Drawing a picture of a cube (okay, drawing a 2-dimensional representation of a cube) helps a lot.

 

[A.T.]

Here is a similar one:

A circuit has N nodes. Each node is connected to every other node via a resistor R. What is the total resistance between two nodes?

Spoiler

The trick in both questions is to find the nodes that are equipotential.