Resistance of a Wire Cube: Diagnol Faces

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Discussion Overview

The discussion revolves around calculating the resistance at the diagonals of the faces of a wire cube, where the wire is segmented into pieces with a specified resistance. The scope includes theoretical considerations and circuit analysis related to electrical resistance in a geometric configuration.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant describes a scenario where a wire is divided into 12 pieces, each with a resistance of 1R, and asks for the resistance at the diagonals of the cube's faces.
  • Another participant expresses confusion regarding the original question, noting that a cube has six faces and requests clarification on the problem.
  • A third participant suggests that the question may pertain to the resistance between two diagonal vertices of the cube and recommends plotting the current paths and creating a circuit diagram for better understanding.
  • A fourth post introduces a different but related problem involving the total resistance between nodes in a circuit with multiple connections, indicating a potential parallel discussion on resistance calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the original question's clarity or intent, and multiple interpretations of the problem exist. The discussion remains unresolved regarding the specific resistance calculation.

Contextual Notes

There is a lack of clarity in the original problem statement, particularly regarding the reference to the "diagonals of the 4 faces" of the cube, which may depend on the interpretation of the cube's geometry and the arrangement of the resistors.

hamzanaveed
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A wire is broken down into 12 pieces so that each piece is of resistance 1R. The pieces are joined together to form a cube. What would be the resistance at the diagnols of the 4 faces of the cube?
 
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welcome to pf!

hi hamzanaveed! welcome to pf! :wink:
hamzanaveed said:
What would be the resistance at the diagnols of the 4 faces of the cube?

i don't understand what you mean (and also a cube has 6 faces) :confused:

anyway, show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
I am assuming you mean the resistance at two diagonal vertices of the cube. Try plotting out all of the different paths that current can take from point A to point B, and then go from there. see if you can put it in the form of a circuit diagram. Drawing a picture of a cube (okay, drawing a 2-dimensional representation of a cube) helps a lot.
 
Here is a similar one:

A circuit has N nodes. Each node is connected to every other node via a resistor R. What is the total resistance between two nodes?


The trick in both questions is to find the nodes that are equipotential.
 

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