Resistor network and 2 voltage sources, help sought

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Discussion Overview

The discussion revolves around a resistor network with two voltage sources, specifically focusing on determining the direction and magnitude of the current in a horizontal wire between two nodes, labeled a and e. Participants are seeking clarification on the calculations related to the current values found in an online solution.

Discussion Character

  • Technical explanation
  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant references a specific problem involving a resistor of 1.00 kΩ and a voltage of 250 V, expressing confusion over the current values of 1.71, 2.71, or 3.71 found in an online solution.
  • Another participant suggests that the original thread title was not applicable and points out that the solution involves redrawing the circuit to replace two parallel resistors with a single equivalent resistor.
  • A later reply states that the current flows from node a to e and claims the magnitude of that current is 0.05 A, although this is not universally accepted.
  • Hints are provided regarding the calculation of equivalent resistance for a 4 Ω resistor in parallel with a 3 Ω resistor, along with equations referencing the reduced circuit.

Areas of Agreement / Disagreement

Participants express confusion over the calculations and the methodology used in the online solution. There is no consensus on the correctness of the current values or the approach taken to solve the problem.

Contextual Notes

Participants have not fully resolved the assumptions regarding the circuit configuration or the specific calculations leading to the current values mentioned. The discussion includes hints for calculating equivalent resistance but does not clarify the overall solution process.

Ashley Shaw
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Hi Ashley Shaw. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Your original thread title of "Physics: Electromagnetism HELP!" was hardly applicable. :eek:

You've found a solution to this exact question. You can see they redrew the circuit, replacing two parallel resistors by a single resistor equivalent to those two in parallel.
 
Last edited by a moderator:
Ashley Shaw said:
don't understand how they got 1.71, 2.71, or 3.71 and solved for I1 or I2.

Hints..

Work out what the equivalent resistance is of a 4 Ohm in parallel with a 3Ohm.

Then with reference to the reduced circuit...

2.71R = 1.71R + R

3.71R = 1.71R + 2R
 

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