The components of a circuit with a voltage source and 2 resistors

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SUMMARY

The discussion focuses on a circuit analysis involving a voltage source of 10V and two resistors in series, R1 at 100 ohms and R2 at 150 ohms. The equivalent resistance (R(eq)) is calculated as 250 ohms, resulting in a current (i_s) of 0.04A. The voltages across the resistors are determined to be 4V across R1 and 6V across R2, with power dissipated by R1 at 0.16W and by R2 at 0.24W. The total power supplied by the source is 0.4W, confirming the calculations are accurate.

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Homework Statement


The components of a circuit with a voltage source and 2 resistors ( series ) has the following values vs = 10V, R1 = 100 , R2 = 150. With i1 leaving the +ve vs and i2 leaving -ve vs ( i.e. i1 entering node A, i2 is entering in the opposite direction of i1 )
Find:
a) Currents through each resistor
b) Voltages across each resistor
c)power dissipated by each resistor
d) power supplied by source
e)equivalent resistance seen by the source


Homework Equations


V=iR
P= iV

P-power
i- current
R- resistance


The Attempt at a Solution

4
Since the circuit is in series i1=i2=is
vs = v1 + v2
vs = isR(eq)

R(eq) = R1 + R2 = 250 ohms

vs / R(eq) = is ====> is = (10v)/(250 ohms) = 0.04A

v1 =isR1
v1 = (0.04 A)(100 ohms) = 4V

v2 = isR2
v2 = (0.04A)(150 ohms) = 6 V

P1= isv1
P1=(0.04A)(4v)=0.16W

P2 =isv2 = (0.04 A) (6V)= 0.24 W

Ps = isvs
Ps = 0.4W


Is there something wrong in my calculations or concept? & what does it mean by "e)equivalent resistance seen by the source"?

Thanks
 
Last edited by a moderator:
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The calculations look OK.

e) is just asking for the total resistance, which you already worked out.

In this case, it is obvious, but sometimes it is important to say which point you are looking from when you talk about input resistance.
So, they say "as seen by the power supply" as if the power supply could "see" what resistance was across it.
 

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