I'm having problem trying to calculate total resistance in resistor arrangement like this one: http://o3xn.files.wordpress.com/2012/04/different.png Before I go into any more detail with the original problem, I just want to say that whenever I get this "closed" type of circuits, I like rearranging them into the "open" type, so that e.g. http://o3xn.files.wordpress.com/2012/04/r_1_20120414.png becomes http://o3xn.files.wordpress.com/2012/04/r_2_20120414.png ------- Okay, back to the original question. First, I observe that potential at point 2 is higher than at point 3, which means that the current flows from 2 to 3 ("down"). This in turn means that there are basically two (parallel) ways for the current to pass this circuit: (the above both) first R, then either 5R or 2R-7R / the two subpaths are in parallel to one another (the below path) first 2R, then 7R This seems to indicate that I can redraw the circuit as follows: http://o3xn.files.wordpress.com/2012/04/different2.png This rearranged circuit is not entirely "open" (2R is connected to the wire in between 2R and 7R) and I have no idea how I should treat this. One of my guesses was that perhaps I am allowed to add another 7R resistor, making the circuit look like this one: http://o3xn.files.wordpress.com/2012/04/different3.png I'm not sure if I can add the extra resistor if it wasn't in the original problem. But it does have two different currents flowing, so maybe?