Resultant Force: 40N in Negative X Direction

[alexmolinavr6]

Resultant force?

A particle is said to be in static equilibrium if the resultant of all forces is applied to it is zero. Find the force that must be applied to a particle that produces static equilibrium if there are two forces, each of 40N applied so that one acts 60o above the positive x-axis and the other 60 below the negative x-axis.
Give the magnitude of the resultant acting in the negative x direction.

 

[berkeman]

A particle is said to be in static equilibrium if the resultant of all forces is applied to it is zero. Find the force that must be applied to a particle that produces static equilibrium if there are two forces, each of 40N applied so that one acts 60o above the positive x-axis and the other 60 below the negative x-axis.
Give the magnitude of the resultant acting in the negative x direction.

Welcome to the PF. You need to show us the Relevant Equations and your Attempt at a Solution, before we can be of tutorial help. What can you say about how to start summing and figuring out the vector equations?

 

[alexmolinavr6]

this is what I was thinking in doing
Taking the magnitude of the given forces

llF1^2ll llF2^2ll

which when plugged in would be something like:

sqrt[(40^2)+(40^2)]

which will give me a F3=56.57N