Resultant Impulse Homework: ΣFΔt = mΔv

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Homework Help Overview

The discussion revolves around understanding the concept of resultant impulse in the context of momentum and forces acting on stationary boulders. The original poster is trying to clarify the meaning of resultant impulse as indicated by their professor, particularly in relation to the equations of impulse and momentum.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between impulse and momentum, questioning how the concept of resultant impulse applies when the boulders are not moving. There is discussion about the forces acting on the boulders and the implications of friction, as well as the need to identify opposing forces.

Discussion Status

Participants are actively engaging in clarifying the definitions and implications of resultant impulse. Some have provided insights into the nature of forces involved, while others are questioning assumptions about the scenario, such as the role of friction and the conditions under which the boulders remain stationary.

Contextual Notes

The problem lacks specific details about the forces acting on the boulders, such as whether friction is present or the direction of the applied forces. This uncertainty is influencing the discussion and the reasoning being explored.

x2017
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Homework Statement


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Homework Equations


ΣFΔt = impulse
mΔv = momentum
ΣFΔt = mΔv

The Attempt at a Solution


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I got the first part of the question (I hope I did it correctly), I just don't understand what my professor means by resultant impulse... Do I use the same equation? Is it going to be the same as a) since the boulders aren't moving?
 
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impulse is the change in momentum(FΔt=ΔP-Newtons 2nd law)
but here ΔP=0=impulse
 
akshay86 said:
impulse is the change in momentum(FΔt=ΔP-Newtons 2nd law)
To clarify, that is for the net (i.e. resultant) impulse.

@x2017 , in the first part, you are correct that they exert the same impulse, but your final sentence is wrong in referring to the weights of the boulders. Why did the boulders not move?
 
haruspex said:
To clarify, that is for the net (i.e. resultant) impulse.

@x2017 , in the first part, you are correct that they exert the same impulse, but your final sentence is wrong in referring to the weights of the boulders. Why did the boulders not move?
Hmmmm... because the force applied by each girl isn't great enough to overcome the force of friction acting on each boulder? (I expect this to be incorrect since friction isn't mentioned in he question at all, it's just the first thing that come to mind!)
 
x2017 said:
Hmmmm... because the force applied by each girl isn't great enough to overcome the force of friction acting on each boulder? (I expect this to be incorrect since friction isn't mentioned in he question at all, it's just the first thing that come to mind!)
We are not told which way they are pushing, but suppose it is horizontal. Neither are we told whether the boulders are simply lying on flat ground, but suppose they are. If there is no opposing horizontal force then the boulders must move. What could the opposing force be?
But you don't need to care what the opposing force is, you just need to deduce there is one. Weight acts vertically.
 

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