Retrieving exact value using Compound angle

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Homework Help Overview

The discussion revolves around retrieving exact values using compound angles, particularly when the angles involved are not standard special angles like 30°, 45°, or 60°. Participants are exploring various methods to express angles and their corresponding trigonometric values.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different ways to express angles, such as using subtraction or addition of known angles. There is a question about whether different methods yield the same results. Some participants attempt to apply the tangent subtraction formula and express concerns about simplification.

Discussion Status

The discussion is active, with participants sharing various approaches to the problem. Some guidance has been offered regarding the simplification of expressions, particularly in relation to rationalizing denominators. There is an ongoing exploration of different interpretations of the problem.

Contextual Notes

Participants are facing challenges with angles that do not correspond to standard values, which may affect their approach. There is also a mention of homework constraints that may limit the methods available for solving the problem.

aeromat
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Homework Statement


compoundanglehelp.png

Homework Equations


cmpdangleformulae.png

The Attempt at a Solution


I'm stuck. I don't know what to do when the angle cannot be the sum or difference of two special angles (like 45,60,30). I tried taking a look at other topics, but there wasn't a clear solution for me to follow.
 
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For b, try 30° - 45° = -15°

For c, 11[itex]\pi[/itex]/12 = [itex]\pi[/itex] - [itex]\pi[/itex]/12, or 175° = 180° - 15° = 180° + 30° - 45°
 
Ok, you showed me more than one way to get to the required angle. Would all the various ways end up giving me the same answer?
 
How about you try each way and see?
 
If I do 45-60, and 30-45 I get (I used tan(a-b), where 'a' is smaller and 'b' is the larger value)

1 - root of 3
------------ <-- divided by
1 + root of 3

correct answer is:

-2 + root of 3.. <-- no denominator

How do they get that?
 
aeromat said:
If I do 45-60, and 30-45 I get (I used tan(a-b), where 'a' is smaller and 'b' is the larger value)

1 - root of 3
------------ <-- divided by
1 + root of 3

correct answer is:

-2 + root of 3.. <-- no denominator

How do they get that?
Multiply the numerator and denominator by the conjugate of the denominator:
[tex]\frac{1 - \sqrt{3}}{1 + \sqrt{3}} \cdot \frac{1 - \sqrt{3}}{1 - \sqrt{3}}=...[/tex]
It's not considered simplified if you have a rational expression with a radical in the denominator, so that's why we do this.
 

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