Reverse Recovery Current of a diode

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Discussion Overview

The discussion centers around the reverse recovery current of a diode when transitioning from forward bias to reverse bias. Participants explore the physical mechanisms behind the appearance of this current, including the behavior of minority carriers and the forces acting on them during the transition.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions whether the reverse current is due to the diffusion of excess minority carriers stored in the diode's P and N regions.
  • Another participant suggests that the driving force for the excess minority charges when reverse voltage is applied is the electric field force, which directs the minority carriers back to their native materials.
  • A later reply indicates that the removal of stored charges occurs through both diffusion and recombination processes, noting that the negative current indicates a flow opposite to that during forward bias.

Areas of Agreement / Disagreement

Participants express varying views on the mechanisms involved in the reverse recovery current, with some focusing on diffusion and others on recombination, indicating that multiple competing explanations remain in the discussion.

Contextual Notes

There are unresolved aspects regarding the specific contributions of diffusion versus recombination in the context of reverse recovery current, as well as the implications of the negative current flow.

tonyjk
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Hello,

When the diode is in forward bias phase and suddenly we apply a reverse bias voltage, the diode takes time to be fully blocked because of the excess of minority charges that are stored in P and N region. Thus a reverse current appears in the diode for a short time before it is blocked. My question is, is this current a diffusion of the excess of minority carriers that are stocked? If yes, why this happens physically speaking? How the current suddenly becomes negative?

Thank you
 
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Hello again,

I am talking about this graph, which force is driving the excess of minority charges when the negative voltage is applied?
 

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Electric field force, F = qE. Minority carriers get stored in the depletion zone under forward bias. When the bias suddenly reverses, the E field of the external source points in a direction that forces the minority carriers back to their native material. Holes stored on the n side are forced to transit back to the p side and vice-versa. Similarly, electrons in the p side are forced back to the n side. Once the stored charge has been removed from the depletion zone and returned to its origin, the "tail current" ceases. Make sense?

Claude
 
tonyjk said:
Hello,

When the diode is in forward bias phase and suddenly we apply a reverse bias voltage, the diode takes time to be fully blocked because of the excess of minority charges that are stored in P and N region. Thus a reverse current appears in the diode for a short time before it is blocked. My question is, is this current a diffusion of the excess of minority carriers that are stocked? If yes, why this happens physically speaking? How the current suddenly becomes negative?

Thank you
When the potential is reversed the minority charges must be cleared out. This occurs both by dffusion and by recombination (holes in the n region recombine with electrons in the n region, and likewise with electrons in the p region). The negative current denotes that the sense of flow is opposite to that during forward bias.
 

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