Rifle shoots bullet into pendulum What am I doing wrong?

  • Thread starter Thread starter WahooMan
  • Start date Start date
  • Tags Tags
    Bullet Pendulum
Click For Summary

Homework Help Overview

The problem involves a rifle bullet impacting a pendulum, with the goal of determining the vertical and horizontal components of the pendulum's maximum displacement after the collision. The context includes concepts from momentum, kinetic energy, and gravitational potential energy.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculations related to momentum and energy transfer, with attempts to find the components of displacement using the Pythagorean theorem. Questions arise regarding the correct measurement of displacement from the pendulum's rest position.

Discussion Status

Some participants express agreement with the original poster's calculations, while others suggest that the displacement should be measured from the original rest position of the pendulum. There is a recognition of a potential misunderstanding regarding the change in vertical position.

Contextual Notes

There is a noted discrepancy in the interpretation of the vertical displacement, with some participants pointing out that the change in height should be 0.24 m rather than the previously calculated 1.9 m.

WahooMan
Messages
22
Reaction score
0

Homework Statement



A 30g rifle bullet traveling 220 m/s buries itself in a 3.0kg pendulum hanging on a 2.1m long string, which makes the pendulum swing upward in an arc. Determine the vertical and horizontal components of the pendulum's maximum displacement.


Homework Equations



p=mv
K=1/2mv^2
Ug=mgy


The Attempt at a Solution



First, I found the momentum of the bullet:

p=mv
p=(0.03kg)(200m/s)
p=6.6kg*m/s

Then I found the velocity of the pendulum after the bullet hits it:

(6.6kg*m/s)/(3.03kg)=2.18m/s

After that I found the Kinetic Energy of the system just after the bullet hits the pendulum:
KE=1/2mv^2
KE=(1/2)(3.03)(2.18)^2
KE=7.19J

Then, because that Kinetic Energy transfers to Gravitational Potential Energy when the pendulum has reached its max height, I set the Kinetic Energy equal to Gravitational Potential Energy.

Ug=mgy
7.19J=(3.03kg)(9.80)(y)
y=0.24m

Using the length of the pendulum (2.1m) as the hypotenuse and (length of the pendulum - y=1.86m) as the y component, I used the Pythagorean Thereom to solve for the x component.

a^2+b^2=c^2
1.86^2+b^2=2.1^2
b^2=2.1^2-1.86^2
b=0.98m

So I got the x component to be 0.98m and the y component to be 1.9m, but MasteringPhysics says I'm wrong. What did I do wrong?
 
Physics news on Phys.org
WahooMan said:
So I got the x component to be 0.98m and the y component to be 1.9m, but MasteringPhysics says I'm wrong. What did I do wrong?
Your work looks fine to me.
 
WahooMan said:
So I got the x component to be 0.98m and the y component to be 1.9m, but MasteringPhysics says I'm wrong. What did I do wrong?
As Doc Al says, your approach is correct. However, displacement should be measured from its original rest position. That is probably why your answer is not jiving. Also, I get .97m for the x component.

AM
 
Did I not measure from the rest position? What would be the correct answer if I did? What exactly did I do wrong?
 
WahooMan said:
Did I not measure from the rest position? What would be the correct answer if I did? What exactly did I do wrong?
You are using 1.9m for the change in y. The block does not change its y position by that amount. You found that it changes by .24 m.

AM
 
Andrew Mason said:
You are using 1.9m for the change in y. The block does not change its y position by that amount. You found that it changes by .24 m.
D'oh! Good catch, AM. (I wasn't paying attention. :redface:)
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
7K
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 8 ·
Replies
8
Views
18K
Replies
3
Views
2K