Ring of Integers Isomorphism Problem

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SUMMARY

The discussion centers on the isomorphism between the ring of integers modulo N, denoted ZN, and the direct product of the rings of integers modulo A and B, denoted ZA x ZB, where A and B are coprime positive integers. The user proposes a mapping function f(n) = (n mod A, n mod B) and successfully demonstrates that it is homomorphic and injective. The conclusion drawn is that since ZN and ZA x ZB share the same cardinality and f is injective, f must also be surjective, thus establishing the isomorphism. The Chinese Remainder Theorem is referenced as a critical tool in this proof.

PREREQUISITES
  • Understanding of ring theory and isomorphisms
  • Familiarity with the Chinese Remainder Theorem
  • Knowledge of modular arithmetic
  • Basic concepts of homomorphisms and injective functions
NEXT STEPS
  • Study the Chinese Remainder Theorem in detail
  • Explore proofs of isomorphisms in ring theory
  • Practice problems involving homomorphic mappings
  • Investigate applications of modular arithmetic in number theory
USEFUL FOR

Mathematics students, particularly those studying abstract algebra, educators teaching ring theory, and anyone interested in the properties of modular arithmetic and isomorphisms.

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Homework Statement
Let N = AB, where A and B are positive integers that are relatively prime. Prove that ZN is isomorphic to ZA x ZB.

The attempt at a solution
I'm considering the map f(n) = (n mod A, n mod B). I've been able to prove that it is homomorphic and injective. Is it safe to conclude, since ZN and ZA x ZB have the same cardinality and f is injective, that f is surjetive? In any case, given an (a, b) in ZA x ZB, I've been trying to find an n such that f(n) = (a, b) without success. Any tips?
 
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Recall the Chinese remainder theorem.
 
Good tip. Thanks.
 

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