Rising Air Bubble in a River: Calculating Radius

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Homework Help Overview

The problem involves calculating the radius of an air bubble as it rises from the bottom of a river, considering the effects of pressure changes due to depth. The subject area includes fluid mechanics and gas laws.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss calculating the pressure at the bottom of the river and how it relates to the volume of the bubble as it rises. There are questions about the relationship between pressure and volume, particularly why pressure is inversely proportional to volume rather than surface area.

Discussion Status

The discussion is exploring the principles of pressure and volume relationships in gases, with some participants providing insights into the definitions of pressure and its independence from surface area. There is no explicit consensus yet, but the conversation is delving into relevant concepts.

Contextual Notes

Participants are working within the constraints of the problem's parameters, including the depth of the river and the properties of the air bubble. The discussion reflects a focus on understanding the underlying physics rather than reaching a final solution.

anand
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Homework Statement


An air bubble of radius 2mm if formed at the bottom of a 3.3m deep river.Calculate radius of bubble as it comes to the surface.
atmospheric pressure=10^5 pa and density of water=1000 kg/m^3
 
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Calculate the pressure at the bottom of the river(depth*density of liquid*graviational acceleration). Let it be P1 and the pressure above the surface of river (i.e equal to the atmosperic pressure) P2.
Then the volume enclosed by the buble change by the factor P1/P2 (pressure is inversely proportional to the volume).
Assuming the buble as a sphere you can easily work out the radius.
 
Why is the pressure inversely proportional to the volume and not the surface area?
 
anand said:
Why is the pressure inversely proportional to the volume and not the surface area?

At constant temperature, when pressure increases gas volume decreases(it is a general observation). Mathematically speaking, when pressure is doubled volume becomes halve of the original volume. So it is evident why volume and pressure are inversely related.

Pressure is independent of surface area. Because pressure is defined as force exerted perpendicularly on unit area(i.e P=F/A). So pressure must not be confused with force. :confused:
 
Thanks a lot!
 

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