RL Circuit Refresher: Solve Total Current

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SUMMARY

The discussion focuses on calculating the total current in a parallel RL circuit using the formula Vin × (1/R - j1/ωL). The user initially calculated the total current incorrectly by applying the wrong formula, resulting in discrepancies in their results. The correct approach involves using the admittance method, where admittances in parallel add together. The final correct calculation for total current should yield a value of 4.47A when using the appropriate formulas and values.

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jendrix
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Hi, I have just been refreshing my theory and was going over a parallel RL circuit, like this one.

vFu2isf.png


The site I was reading had this for the total current

wSOg5fX.png


I tried some values as a test but it doesn't give me the correct answer, for total current. eg if I set
V=10V
R=2.5ohm
jXl=5ohm

Then IR=10/2.5 =4A

IL=10/5=2A

IT=√42 +22 =4.47A

However when I try the formula from the second answer I get 10/(2.5-2j) which following the maths gives me 2.44+1.95j=3.12A

Am I going wrong somewhere or is it the formula?Thanks
 

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jendrix said:
However when I try the formula from the second answer I get 10/(2.5-2j) which following the maths gives me 2.44+1.95j=3.12A

Admittances in parallel add. That should be your approach.

upload_2018-8-8_21-15-30.png

A 'Site', you said ? If it's on the internet it must be right, eh ? See my signature.....

see if that works any better.

old jim
 

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Oops ----- make that it equals Vin X ( 1/R -j1/ωL )

i put my j in wrong place . :cry:
 
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jim hardy said:
Oops ----- make that it equals Vin X ( 1/R -j1/ωL )

i put my j in wrong place . :cry:

Seems we can't even trust Old Jim when he posts at the internet with a computer, cause we can never trust a computer with anything important :-p

Ok seriously speaking that was a minor mistake, I didn't notice it either, I just noticed the huge mistake in the algebra in the OP.
 
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i do that all the time. I'm just clumsy.

Thanks @Delta2
 
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jim hardy said:
i do that all the time. I'm just clumsy.

Thanks @Delta2

Thanks Jim for clearing that up
 
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