Rock whirling in vertical circle

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SUMMARY

A rock whirling in a vertical circle with a radius of 8 meters requires specific calculations to determine the speed at which tangential and radial accelerations are equal when the string makes a 37-degree angle with the vertical. The gravitational acceleration is 9.8 m/s². The relationship derived from the discussion indicates that the speed (v) can be calculated using the formula v² = g * r * sin(θ), where θ is the angle with respect to the vertical.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Familiarity with trigonometric functions, specifically sine
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of centripetal acceleration in circular motion
  • Learn how to apply trigonometric functions in physics problems
  • Explore the derivation of motion equations in vertical circular paths
  • Investigate the effects of varying angles on tension and acceleration in circular motion
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of objects in circular motion, particularly in vertical scenarios.

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a rock whirls in a vertical circle of radius 8m. acceleration of gravity 9.8m/s^2

what must the speed be to have tangential=radial acceleration when the string makes a 37 angle with respect to the vertical?

is it Wsinangel=ma

v=Wsinangle*r/m)^1/2 ?
 
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If W is mg, then yes.

v² = gr.sin@
 

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