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StrawHat
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Homework Statement
Homework Equations
r * \alpha = atan
r * \omega^2 = arad
The Attempt at a Solution
arad = (L/2)(3g/L) = 3g/2
atan = (L/2)(3g/2L) = 3g/4
Rod on a pivot: Linear acceleration and reaction forces
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SUMMARY
The discussion focuses on the calculations of linear acceleration and reaction forces for a rod on a pivot. Key equations utilized include the angular acceleration formula \( r \cdot \alpha = \tan \) and the radial acceleration formula \( r \cdot \omega^2 = a_{rad} \). The correct radial acceleration was determined to be \(-\frac{3g}{2}\) after considering the proper signs of the components. The discussion emphasizes the importance of accurately applying negative signs in reaction force calculations.
PREREQUISITES- Understanding of angular motion equations, specifically \( r \cdot \alpha \) and \( r \cdot \omega^2 \).
- Familiarity with concepts of linear acceleration and reaction forces in physics.
- Knowledge of the significance of sign conventions in physics calculations.
- Basic proficiency in solving equations involving gravitational acceleration (g).
- Study the principles of angular motion and how they relate to linear acceleration.
- Learn about the role of sign conventions in physics, particularly in dynamics.
- Explore the derivation and application of reaction force equations in different mechanical systems.
- Investigate the effects of varying lengths and masses on the dynamics of pivot systems.
Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of angular motion and reaction forces in real-world applications.
r * \alpha = atan
r * \omega^2 = arad
arad = (L/2)(3g/L) = 3g/2
atan = (L/2)(3g/2L) = 3g/4
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How did you get this?StrawHat said:
Looks OK. (But don't forget the proper signs of the components.)
- #3
StrawHat
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I got arad = 3g/2 by multiplying r by ω2.
EDIT: It was actually -3g/2.
Going onto the reaction forces, I thought it was just R = ma, but apparently that's not the case...
Re-EDIT: Got it. I just needed to add the negative signs.
EDIT: It was actually -3g/2.
Going onto the reaction forces, I thought it was just R = ma, but apparently that's not the case...
Re-EDIT: Got it. I just needed to add the negative signs.
Last edited:
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