1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rod on a pivot: Linear acceleration and reaction forces

  1. Jul 17, 2012 #1
    1. The problem statement, all variables and given/known data
    6Wg77.png


    2. Relevant equations
    r * [itex]\alpha[/itex] = atan
    r * [itex]\omega^2[/itex] = arad


    3. The attempt at a solution
    arad = (L/2)(3g/L) = 3g/2
    atan = (L/2)(3g/2L) = 3g/4
     
  2. jcsd
  3. Jul 17, 2012 #2

    Doc Al

    User Avatar

    Staff: Mentor

    How did you get this?
    Looks OK. (But don't forget the proper signs of the components.)
     
  4. Jul 17, 2012 #3
    I got arad = 3g/2 by multiplying r by ω2.

    EDIT: It was actually -3g/2.

    Going onto the reaction forces, I thought it was just R = ma, but apparently that's not the case...

    Re-EDIT: Got it. I just needed to add the negative signs.
     
    Last edited: Jul 17, 2012
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Rod on a pivot: Linear acceleration and reaction forces
  1. Pivot Force Reactions (Replies: 3)

Loading...