Rod on a pivot: Linear acceleration and reaction forces

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StrawHat
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Homework Statement


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Homework Equations


r * [itex]\alpha[/itex] = atan
r * [itex]\omega^2[/itex] = arad


The Attempt at a Solution


arad = (L/2)(3g/L) = 3g/2
atan = (L/2)(3g/2L) = 3g/4
 
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StrawHat said:
arad = (L/2)(3g/L) = 3g/2
How did you get this?
atan = (L/2)(3g/2L) = 3g/4
Looks OK. (But don't forget the proper signs of the components.)
 
I got arad = 3g/2 by multiplying r by ω2.

EDIT: It was actually -3g/2.

Going onto the reaction forces, I thought it was just R = ma, but apparently that's not the case...

Re-EDIT: Got it. I just needed to add the negative signs.
 
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