Roll 6 Dice: Solve Probability Puzzle!

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On average, how many times do you need to roll six dice together to see all six different numbers turn up within a single such group roll?
 
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CompuChip said:
64.8 times?

I agree, except for the .8 :)
 
I agreed with 64.8, for the following reasons:

There are 6! ways of throwing all six values and 66 possible results, so the probability in each throw is 6!/66 = (1*2*3*4*5*6)/(6*6*6*6*6*6) = (4*5)/(6*6*6*6) = 5/(3*3*6*6) = 5/324.

The average interval between such throws (or, as in this case, before the first such throw) is therefore the reciprocal of this, 324/5 = 64.8, as usual for a Poisson distribution.