Rolling 4 Identical Numbers: Probability

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Homework Help Overview

The discussion revolves around calculating the probability of rolling exactly four identical numbers when five dice are rolled. Participants are exploring the combinatorial aspects of the problem within the context of probability theory.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to calculate the probability using different methods, including specific arrangements and combinatorial choices. Questions arise regarding the correct application of binomial coefficients and the reasoning behind the number of ways to choose the identical dice.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with some participants questioning the validity of their methods and seeking clarification on combinatorial principles. Guidance has been offered regarding the need for a systematic approach to the probability calculation.

Contextual Notes

Some participants express uncertainty about their understanding of the problem and the methods being used, indicating that this is part of their study guide questions. There is a mention of needing to develop the answer step-by-step rather than making random attempts.

csc2iffy
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Homework Statement



If someone could just check my work, thanks!
If five dice are rolled once each, what is the probability of rolling exactly 4 identical numbers?

Homework Equations


The Attempt at a Solution



This is what I have:
(1)(1/6)(1/6)(1/6)(5/6)=5/1296
 
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csc2iffy said:

Homework Statement



If someone could just check my work, thanks!
If five dice are rolled once each, what is the probability of rolling exactly 4 identical numbers?

Homework Equations


The Attempt at a Solution



This is what I have:
(1)(1/6)(1/6)(1/6)(5/6)=5/1296

That's the probability of doing it in a specific way. Say, first four identical, last one not identical. The problem doesn't specify any particular way.
 
Ok, so would it be this instead?
(6)(1/6)3(5/6)
 
csc2iffy said:
Ok, so would it be this instead?
(6)(1/6)3(5/6)

No. Why '6'? How many ways are there to choose the four identical dice out of five dice?
 
i'm not sure, this is one of my study guide questions and this is why I'm asking...
 
csc2iffy said:
i'm not sure, this is one of my study guide questions and this is why I'm asking...

How many ways to choose 4 objects from 5? It's a binomial coefficient. It's a combinatorial thing. http://en.wikipedia.org/wiki/Binomial_coefficient
 
Last edited:
I took a break from this problem but here is my newest attempt:
choose(5,4) = 5
so is it... 5(1/6)3(5/6)?
 
csc2iffy said:
I took a break from this problem but here is my newest attempt:
choose(5,4) = 5
so is it... 5(1/6)3(5/6)?

Well, yes. Doesn't that seem more right to you than the first try?
 
csc2iffy said:

Homework Statement



If someone could just check my work, thanks!
If five dice are rolled once each, what is the probability of rolling exactly 4 identical numbers?


Homework Equations





The Attempt at a Solution



This is what I have:
(1)(1/6)(1/6)(1/6)(5/6)=5/1296

I think your basic approach is risky: you need to develop the answer step-by-careful step, rather than flailing around and writing down some almost random answers. If you need to keep asking "Am I right"?..."OK, what about now?..." it indicates that you are not at all confident about what you are doing. You would likely be more confident if you were more systematic. Ask yourself the following: suppose the 4 identical numbers are all 1. What would be the probability of that (that is, of getting 4 1's and 2 non-1's)? Think about getting four 2's (instead of 4 1's), then four 3's, etc. Does it matter what the number is? Can you put this all together?

RGV
 

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