1. The problem statement, all variables and given/known data A cylinder is placed on bars.The separation of each bar is l.The cylinder is then pulled with a force F through its center.Find the terminal velocity of the object.Assume l<<R and the ball rolls without slipping. 2. Relevant equations 1/2 mv^2 +1/2 Iω^2 = kinetic energy Work is F*distance 3. The attempt at a solution My thought is that when the work done by the force is equal to the energy loss due to the change of axis of rotation ,the velocity will be constant. Thus,if its velocity before the collision with the new ridge is Vo then after the collision it will be V'.The distance it travels after every ridge is l/2.So the work is F*L/2.This work is equal to the kinetic energy loss,but I cannot figure out what V' is ? Can anyone give me advice or if my idea of this problem is correct ? Thanks in Advance !