Roots of Polynomials: Finding g(y) with y1, y2, y3

  • Thread starter Thread starter mattewmath
  • Start date Start date
  • Tags Tags
    Polynomials Roots
Click For Summary
SUMMARY

The discussion focuses on deriving a polynomial g(y) of third degree with roots defined as y1=x1/(x2+x3-q), y2=x2/(x1+x3-q), and y3=x3/(x1+x2-q), where x1, x2, x3 are the roots of the polynomial f(x)=x³+px+q. Participants emphasize the importance of factoring polynomials based on their roots, specifically using the form y = (x - r1)(x - r2)(x - r3). This approach is essential for constructing the desired polynomial g(y) from the given roots.

PREREQUISITES
  • Understanding of polynomial functions and their roots
  • Familiarity with polynomial factoring techniques
  • Knowledge of rational coefficients in polynomials
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study polynomial root-finding methods in depth
  • Learn about polynomial division and its applications
  • Explore the Rational Root Theorem for polynomial equations
  • Investigate the implications of Vieta's formulas in polynomial relationships
USEFUL FOR

Students studying algebra, mathematicians interested in polynomial theory, and educators teaching polynomial equations and their properties.

mattewmath
Messages
2
Reaction score
0

Homework Statement



Let x1, x2, x3 are the roots of the polynomial f(x)=x3+px+q, where f(x)[tex]\in[/tex]Q[x], p[tex]\neq[/tex]0. Find a polynomial g(y) of third degree with roots:

y1=x1/(x2+x3-q)
y2=x2/(x1+x3-q)
y3=x3/(x1+x2-q)

Homework Equations





The Attempt at a Solution



Any ideas? Thank you.
 
Physics news on Phys.org
Not guaranteeing a solution, but recall that a polynomial with roots can always be factored into the form y = (x - r1)(x - r2)(x - r3) where rn is a unique root. Try this with your three roots.
 
Thank you for the advice. I will use it.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K