Rotation Dynamics mastering physics 10.32

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SUMMARY

The discussion focuses on calculating the work done by an airplane propeller with a length of 2.08 m and a mass of 117 kg, subjected to a constant torque of 1950 Nm. After 5 revolutions, the correct formula for work is established as W = Torque × Angle, where the angle is calculated as 5 × 2π radians. The average power is derived from the formula P = Torque × Angular Velocity, with the angular velocity determined to be 53.9 rad/s. The initial calculations were incorrect, prompting a reevaluation of the formulas used.

PREREQUISITES
  • Understanding of rotational dynamics concepts
  • Familiarity with torque and its units (Nm)
  • Knowledge of angular displacement and its calculation
  • Basic principles of power in rotational systems
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  • Study the relationship between torque and angular displacement in rotational motion
  • Learn how to calculate work done in rotational systems
  • Explore the derivation of average power in rotational dynamics
  • Investigate the implications of mass and length on rotational inertia
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An airplane propeller is 2.08 m in length (from tip to tip) and has a mass of 117 kg. When the airplane's engine is first started, it applies a constant torque of 1950 Nm to the propeller, which starts from rest.

How much work in joules is being done after 5 revolutions?

This is what I did: (1.04*1950)*(5*2*pi). Mastering physics says it is close, but not correct.
 
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figured that out: (1950)*(5*2pi)
Now I need to calculate the average power. power=T_z*w_z
=1950 Nm *53.9 rads/s.

mastering physics says this is incorrect. Any ideas?
 

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