Rotational Motion About a Fixed Axis

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Homework Help Overview

The problem involves two identical thin rectangular sheets with different axes of rotation and the same applied torque. The original poster seeks to determine the time it takes for the second sheet to reach the same angular velocity as the first, which reaches its final angular velocity in 6.5 seconds.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between torque, moment of inertia, and angular acceleration, noting that the sheets have different moments of inertia due to their orientations. There is uncertainty about how to proceed without knowing the mass or angular acceleration.

Discussion Status

Some participants have provided equations relating torque and moment of inertia, suggesting a method to find the time for the second sheet based on the first. However, there remains confusion about the necessity of mass and angular acceleration, and no consensus has been reached on how to proceed without these values.

Contextual Notes

Participants highlight that both sheets are identical and that the same torque is applied, but they question how the differing orientations affect the moment of inertia and the resulting calculations. There is a lack of explicit values for mass and angular acceleration, which complicates the discussion.

wchvball13
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Homework Statement


Two thin rectangular sheets (0.23 m 0.35 m) are identical. In the first sheet the axis of rotation lies along the 0.23 m side, and in the second it lies along the 0.35 m side. The same torque is applied to each sheet. The first sheet, starting from rest, reaches its final angular velocity in 6.5 s. How long does it take for the second sheet, starting from rest, to reach the same angular velocity?


Homework Equations


[tex]\tau=(mr^{2})\alpha[/tex]
[tex]E\tau=I\alpha[/tex]
[tex]I=(1/3)ML^{2}[/tex]

The Attempt at a Solution


I don't know how to start if you don't have a mass...or the angular acceleration
 
Last edited:
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w = wo + alpha*t
Torque = I*alpha
Alpha = Torque/I
wo = 0 Torque is same, final angular velocity is same.
Therefore (Torque/I1)t1 = (Torque/I2)t2
I1 = (M* 0.35^2)/3 and I2 = ( M*0.23^2)/3
 
Last edited:
I don't know how to start if you don't have a mass...or the angular acceleration
The point is that the sheets are identical and the same torque is applied, but the moment of inertias will be different because of the different orientation, which means a different value for L in the expression for moment of inertia.
 
I understand both of your replies, but I still don't understand how I can solve it if I don't have M or alpha
I1 = (M* 0.35^2)/3 and I2 = ( M*0.23^2)/3
 
w = wo + alpha*t...(1)
Torque = I*alpha...(2)
Alpha = Torque/I...(3)
wo = 0 Torque is same, final angular velocity is same.
Therefore (Torque/I1)t1 = (Torque/I2)t2...(4)
I1 = (M* 0.35^2)/3 and I2 = ( M*0.23^2)/3
From eq. 2 you can find alpha. Put this value in eq.1. Put wo = 0. and equate w for I1 and I2. In the final expression M gets canceled out.
 
apparently I suck at physics because I can't even understand how you can find Alpha from eq. 2. Once I figure out that I can find the rest but for right now all I have is I1=.0408 and I2=.0176...and that's if I ignore the masses since they're equal...
 
From eq.4 you get t1/I1 = t2/I2, because torque is same. t1 = 6.5 s. Find t2.
 

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