Rotational Motion of a wheel turning

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Falinox
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Homework Statement


A wheel starting from rest accelerates at 1.2 rad/s² counterclockwise.
A) How long does it take to turn through 60 revolutions?
B)What is the rotational speed at that time?

2. The attempt at a solution

I converted 1.2rad/s² to 1.885 rev/s² by dividing by 2πrad (2 pi radians).
So where can I go from here?

Once I find the time in part A I can use the fact that ω=Δθ/ΔT to find the "rotational speed" correct?
 
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Welcome to PF!

Hi Falinox! Welcome to PF! :wink:
Falinox said:
I converted 1.2rad/s² to 1.885 rev/s² by dividing by 2πrad (2 pi radians).
So where can I go from here?

Once I find the time in part A I can use the fact that ω=Δθ/ΔT to find the "rotational speed" correct?

(btw, always leave a space between the number and the unit)

No, you need to use the standard constant acceleration equations, using angular displacement speed and acceleration instead of the linear versions. :smile:
 
and i suggest you use radians rather than revolutions; the equations look much nicer that way.
 


tiny-tim said:
Hi Falinox! Welcome to PF! :wink:(btw, always leave a space between the number and the unit)

No, you need to use the standard constant acceleration equations, using angular displacement speed and acceleration instead of the linear versions. :smile:


Thanks for the reply!

ω²=ω₀²+2αθ
Given: ω₀=0 rad/s, α=1.2 rad/s²

Is θ my 60 rev? (maybe convert 60 rev to rad?)
 
that is the right idea, and yes, theta=60rev, but make sure your units all match before plugging things in. your formula is only true if you use radians, so i would recommend that.