Row Echelon Form Homework - Finding Mistake

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The discussion revolves around converting a 3x3 matrix into row echelon form, with the user expressing confusion over their row operations. They attempt various row transformations but struggle to achieve the correct form, leading to discrepancies in the determinants of the original matrix and the resulting upper triangular matrix. The user calculates the determinant of the original matrix as 84, while the determinant of their upper triangular matrix comes out to 336, indicating an error in their operations. Other participants suggest continuing with additional row operations to reach the identity matrix and clarify that the determinant of the upper triangular matrix should match the original matrix's determinant. The user remains uncertain about where their mistake lies in the process.
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Homework Statement


i'm trying to put the 3x3 matrix: [4 2 6]
[ 2 8 2]
[-1 3 1]
into row echelow from.
but i don't know where I'm goin wrong in my row operations. could some1 please tell me where i hav made the mistake.





Homework Equations





The Attempt at a Solution



[4 2 6] [4 2 6 ] [4 2 6]
[2 8 2] r2->r2+2r3 [0 14 4] r3-> 4r3 [0 14 4]
[-1 3 1] [-1 3 1] [-4 12 4]


r3->r3+r1 [4 2 6 ] r3->r3-r2 [4 2 6]
[0 14 4] [0 14 4] :confused:
[0 14 10 [0 0 6]
 
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Divide the second row by 14, then subtract twice the second row from the first row. Figure out the rest from there
 
What makes you think that that's wrong? With a few more operations you can get to I (the identity matrix) if that's what you need.
 
? I'm trying to find the LU decomposition so U is jst an upper triangular matrix and that's what my answer above is. and from the fact that
det(A) = det(LU) = det(L)det(U) = det(U) as det(L) = 1 the determinant of A has to be equal to the determinant of U. i worked out the determinant of A to be 84 but the determinant of U = 4((14x6)-(4x0))-2((0x6)-(4x0))+6((0x0)-(14x0)) = 4x14x6 = 336 which does not equal 84! i still dont' get what I've done wrong :(
 
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