Rudin Ch 5, #29: Uniqueness Theorem for Systems of ODEs

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SUMMARY

The discussion focuses on deriving a uniqueness theorem for solutions of a system of ordinary differential equations (ODEs) as specified in Rudin Chapter 5, exercise 29. The system involves continuous real functions \( f(x) \) and \( g_j(x) \) defined on the interval \([a,b]\) and is subject to initial conditions \( y(a)=c_1 \), \( y'(a)=c_2 \), and \( y^{(k-1)}(a)=c_k \). The participants emphasize the importance of correctly formulating the system and initial conditions to establish the uniqueness of solutions.

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Homework Statement



Specialize exercise 28 by considering the system

\y&#039;= y_{j+1} j=(1,...,k-1)<br /> y&#039;_{k}= f(x)-\sum g_{j}(x)y_{j} where the summation runs from j=1 to j=k, and g_{j} and f are continuous real functions on [a,b], and derive a uniqueness theorem for solutions of the equation<br /> <br /> y^{k}+g_{k}(x)y^{k-1}+...+g_{2}y&#039;+g_{1}(x)y = f(x)<br /> <br /> subject to initial conditions<br /> <br /> y(a)=c_{1}, y&#039;(a)= c_{2}, y^{k-1}(a) = c_{k}.[\tex]<br /> <br /> <br /> <br /> <h2>Homework Equations</h2><br /> <br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br />
 
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Hi Quantumpencil! :smile:

(you use the wrong slash: :wink:)
Quantumpencil said:
Specialize exercise 28 by considering the system

y&#039;= y_{j+1}, j=(1,...,k-1),\ y&#039;_{k}= f(x)-\sum g_{j}(x)y_{j} where the summation runs from j=1 to j=k, and g_{j} and f are continuous real functions on [a,b], and derive a uniqueness theorem for solutions of the equation

y^{k}+g_{k}(x)y^{k-1}+...+g_{2}y&#039;+g_{1}(x)y = f(x)

subject to initial conditions

y(a)=c_{1}, y&#039;(a)= c_{2}, y^{k-1}(a) = c_{k}

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
yeah, so I didn't realize I made this thread; it's incomplete. Could I get it locked?

The actual thread I need help on is further-down and contains the good tech + information about how I think the solution will work out.

https://www.physicsforums.com/showthread.php?t=297047

This is the link to the actual topic.
 
Last edited:

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