Rutherford Scattering cross section

[SuperPokenerd]

Homework Statement

Integrate the rutherford cross section over the backward hemisphere to get 4pi(sigma0(E))

Homework Equations

Rutherford cross section is sigma0(E)/sin^4(theta/2)

The Attempt at a Solution

When I integrate this with the limits pi/2 to pi i get sigma0(E)*(8/3) i don't know what I'm doing wrong.

 

[NeoDevin]

Are you sure you have your integration limits correct?

 

[SuperPokenerd]

I thought so, since the problem says that theta goes between pi/2 and pi i.e. large angle scattering is from 90-180 degrees. I don't see how I'm supposed to get it to be 4pi instead of 8/3.

 

[NeoDevin]

Never mind my previous response, I was confusing this with a different problem I was solving earlier.

As near as I can tell, your solution appears to be correct.