S there a way to calculate this using the thermodynamic identity?

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SUMMARY

The discussion focuses on calculating the increase in entropy for a liter of air heated at constant pressure until its volume doubles. Participants explore using the thermodynamic identity, specifically the formula dS = (dS/dU)dU + (dS/dV)dV, to derive the entropy change without employing the Sackur-Tetrode equation. The equation ΔS = ∫ dQ_{rev}/T = nC_p ln(T_f/T_i) is also mentioned as a potential method for calculating entropy change in this scenario.

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Shaybay92
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Homework Statement


A liter of air, initially at room temperature and atmospheric pressure, is heated at constant pressure until it doubles in volume. Calculate the increase in its entropy during this process.

Is there a way to calculate this using the thermodynamic identity (ie. without the Sackur Tetrode equation??) I was trying to use this formula, setting dV = V_initial... Any ideas?

dS = (dS/dU)dU + (dS/dV)dV
 
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Shaybay92 said:

Homework Statement


A liter of air, initially at room temperature and atmospheric pressure, is heated at constant pressure until it doubles in volume. Calculate the increase in its entropy during this process.

Is there a way to calculate this using the thermodynamic identity (ie. without the Sackur Tetrode equation??) I was trying to use this formula, setting dV = V_initial... Any ideas?

dS = (dS/dU)dU + (dS/dV)dV
What is the matter with:

[tex]\Delta S = \int dQ_{rev}/T = nC_p\ln(T_f/T_i) ?[/tex]

AM
 

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