Scalar potential and line integral of a vector field

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The discussion revolves around solving a problem involving the scalar potential and line integral of a vector field. The user initially defined the vector field F(r) and attempted to integrate it, yielding a result of 1/2*(B^2 - A^2). However, upon reviewing the hint, they noted the presence of an additional term (B^2 + A^2)/2 and a constant "c," which were missing from their calculations. The user suspects that they may have incorrectly defined F(r) and suggests that the correct approach involves using the provided definition from a previous problem. The goal is to find a scalar potential function phi(r) that satisfies the line integral relationship.
alecst
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Homework Statement



nSlbe.png


Homework Equations



Given above.

The Attempt at a Solution



I attempted this problem first without looking at the hint.

I've defined F(r) as (B+A)/2 + t(B-A)/2, with dr as (B-A)/2 dt . Thus F(r)dr = ((B+A)/2)*((B-A)/2)+((B-A)/2)^2 dt

When I integrate this from -1 to 1 I get 1/2*(B^2-A^2).

When I then looked at the hint, I saw it mentioned another (B^2+A^2)/2 term and another "c," neither of which I have, and my integrand has no "tau" squared element either. Is there a point where I went wrong here?
 
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I'm guessing that you don't get to define F(r) but instead have to use the one given to you in problem 4.01, whatever that is.
 
The idea is to used the derived formula to solve the next problem, which is find a scalar potential function phi(r) such that the line integral F(B,A) (as in 4.02) = phi(B)-phi(A). So it's clear I need to solve this in terms of B and A.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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