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physnut_05

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In scattering between incident neutrons and target protons at rest, show that the angle between the two scattered particles is always 90 degrees.

I have set up the conservation of energy and momentum equations and have:

Energy: T

_{n}=T'

_{n}+T

_{p}

Momentum: p

_{n}=p'

_{n}*cos(X)+p

_{p}*cos(Y) AND p'

_{n}*sin(X)=p

_{p}*sin(Y)

Here X and Y are the angles between the scattered neutron and proton with respect to the horizontal.

I've manipulated these around, found an expression for cos(X), but that doesn't seem to get me much of anywhere. A bump in the correct direction would be appreciated.