Understanding the Schwarzschild Coordinate r in Spherical Symmetric Spacetime

Vrbic
Messages
400
Reaction score
18
Schwarzschild coordinate "r"

Hello, I am a newguy here, so if my question don't belong to this section, please let me know.
My question:
In spherical symmetric spacetime discrabed by Schwarzschild coordinate ds2=-a(r)dt2+b(r)dr2+r2(dΘ2+Sin2(Θ)d\varphi2), "r" is defined as r=\sqrt{A/(4\pi)} where "A" is an area of sphere dΘ2+Sin2(Θ)d\varphi2. What is relation between "r" and real distance from the center of coordinate?

Thank you all.
 
Physics news on Phys.org
Vrbic said:
Hello, I am a newguy here, so if my question don't belong to this section, please let me know.
My question:
In spherical symmetric spacetime discrabed by Schwarzschild coordinate ds2=-a(r)dt2+b(r)dr2+r2(dΘ2+Sin2(Θ)d\varphi2), "r" is defined as r=\sqrt{A/(4\pi)} where "A" is an area of sphere dΘ2+Sin2(Θ)d\varphi2. What is relation between "r" and real distance from the center of coordinate?

Thank you all.

In both SR and GR, there is no such thing as 'real distance' (in SR, it is frame dependent, in GR there is commonly no unique definition of it; there are distance conventions that can be adopted, and this r coordinate is an example). In this case, there may no center, even mathematically: you could have and event horizon, with a singularity inside, in which case there is timelike world line that in any way represents the history of a center.
 
So if I want to know exact radial distance between to evens only I can do is ∫grrdr with limits of my r1,r2. Is it right?
 
Vrbic said:
So if I want to know exact radial distance between to evens only I can do is ∫grrdr with limits of my r1,r2. Is it right?
Should be ∫√grrdr, but yes, that's basically the right idea.
 
Some remarks in addition to the missing square root:

It might be helpful to recall from special relativity that "real distance" depends on the frame of reference, it's not an observer independent property in special relativity. Being observer dependent, the adjective "real" may be confusing when applied to distance, since different observers measure different distances.

GR doesn't have exactly the same notion of "frame of reference" as SR. But in this case you can consider that what you are computing with your formula is the distance as measured by a static observer. Static observers are observers that have constant Schwarzschild coordinates, they are basically "at rest" in the Schwarzschild coordinate system.
 
Last edited:
Note that in the case where there's an event horizon, \sqrt{g_{rr}} becomes imaginary inside the horizon. Physically, there are no static observers inside the horizon.
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
In this video I can see a person walking around lines of curvature on a sphere with an arrow strapped to his waist. His task is to keep the arrow pointed in the same direction How does he do this ? Does he use a reference point like the stars? (that only move very slowly) If that is how he keeps the arrow pointing in the same direction, is that equivalent to saying that he orients the arrow wrt the 3d space that the sphere is embedded in? So ,although one refers to intrinsic curvature...
So, to calculate a proper time of a worldline in SR using an inertial frame is quite easy. But I struggled a bit using a "rotating frame metric" and now I'm not sure whether I'll do it right. Couls someone point me in the right direction? "What have you tried?" Well, trying to help truly absolute layppl with some variation of a "Circular Twin Paradox" not using an inertial frame of reference for whatevere reason. I thought it would be a bit of a challenge so I made a derivation or...

Similar threads

Back
Top