Secant Equation for Buckling and Yielding in Eccentrically Loaded Structures

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SUMMARY

The discussion centers on the application of the secant equation in analyzing eccentrically loaded structures, specifically regarding buckling and yielding. Participants clarify that the secant formula is utilized to determine yielding stress along the yy-axis, while the Euler buckling load is critical for the xx-axis. It is established that the column will fail by buckling about the weak xx-axis before yielding occurs about the major yy-axis due to the eccentric loading. The conversation emphasizes the importance of understanding combined bending and axial stresses in structural analysis.

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  • Familiarity with bending and axial stress concepts
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Homework Statement


In the following example , the secant equation circle part) is used to find the max stress when the whole thing is subjected to force P before buckling , am i right ?
Why the author wrote it as the yielding equation ? And why the author use 2 equation for yy axis ?

Homework Equations

The Attempt at a Solution


IMO , there green circle part is worn g, and the equation not exist at all , because the P is loaded eccentrically from yy axis
 

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fonseh said:

Homework Statement


In the following example , the secant equation circle part) is used to find the max stress when the whole thing is subjected to force P before buckling , am i right ?
Why the author wrote it as the yielding equation ? And why the author use 2 equation for yy axis ?

Homework Equations

The Attempt at a Solution


IMO , there green circle part is worn g, and the equation not exist at all , because the P is loaded eccentrically from yy axis
The author appears to have made an error when calculating the Euler buckling load for the major y y-axis by using K = 2 when K should be 1, but anyway, weak axis buckling about x x-axis controls for Euler buckling. But about the major y y axis, the loading is eccentrically applied, which means that there is also bending stress about that axis , and the secant formula is used to be sure that under bending and axial stresses the column will not fail by yielding under the combined bending and axial stresses about the yy axis before it buckled about the xx axis . It doesn't , so weak axis bucking about xx axis controls design.
 
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PhanthomJay said:
which means that there is also bending stress about that axis , and the secant formula is used to be sure that under bending and axial stresses the column will not fail by yielding under the combined bending and axial stresses about the yy axis before it buckled about the xx axis .
i still don't understand , what is the usage of secant formula , can you explain further ?
 
PhanthomJay said:
secant formula is used to be sure that under bending and axial stresses the column will not fail by yielding under the combined bending and axial stresses about the yy axis before it buckled about the xx axis
So , what we get from the secant equation is yielding stress , it's not buckling stress ?
 
PhanthomJay said:
The author appears to have made an error when calculating the Euler buckling load for the major y y-axis by using K = 2 when K should be 1, but anyway, weak axis buckling about x x-axis controls for Euler buckling. But about the major y y axis, the loading is eccentrically applied, which means that there is also bending stress about that axis , and the secant formula is used to be sure that under bending and axial stresses the column will not fail by yielding under the combined bending and axial stresses about the yy axis before it buckled about the xx axis . It doesn't , so weak axis bucking about xx axis controls design.
Do you mean we use both the euler equation and secant equation to find out the max load first , then we take the smallest Pmax of them as the critical load . The larger Pmax is considered as yielding stress ?
 
PhanthomJay said:
secant formula is used to be sure that under bending and axial stresses the column will not fail by yielding under the combined bending and axial stresses about the yy axis before it buckled about the xx axis
http://www.continuummechanics.org/eccentriccolumnbuckling.html

in here , i was told that the for eccentrical loaded column , it will break by yielding first before buckling ...
 
fonseh said:
http://www.continuummechanics.org/eccentriccolumnbuckling.html

in here , i was told that the for eccentrical loaded column , it will break by yielding first before buckling ...
the column will fail by buckling first about the weak xx axis before it ffails by yielding about the major yy axis, because the critical load is less about xx than it is about yy. You should note that there is no eccentricity about the xx axis. So secant formula does not apply about that axis. Understood? This is complex stuff. Get back to the basics.
 
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PhanthomJay said:
the column will fail by buckling first about the weak xx axis before it ffails by yielding about the major yy axis, because the critical load is less about xx than it is about yy. You should note that there is no eccentricity about the xx axis. So secant formula does not apply about that axis. Understood? This is complex stuff. Get back to the basics.
So , secant formula only apply for yy axis ?
Secant formula is used to find the yielding stress about yy axis as stated my the author ?
 
PhanthomJay said:
the column will fail by buckling first about the weak xx axis before it ffails by yielding about the major yy axis, because the critical load is less about xx than it is about yy. You should note that there is no eccentricity about the xx axis. So secant formula does not apply about that axis. Understood? This is complex stuff. Get back to the basics.
why for the yy axis , it's fail by yielding , not fail by buckling ?
 
  • #10
so , when the load is applied eccentricaly , the structure will fail by yielding ?
 
  • #11
fonseh said:
So , secant formula only apply for yy axis ?
Secant formula is used to find the yielding stress about yy axis as stated my the author ?
yes , both correct
fonseh said:
why for the yy axis , it's fail by yielding , not fail by buckling ?
because you have bending stresses and axial compression stresses that combine to reach yield stress at a load less than the critical buckling load
fonseh said:
so , when the load is applied eccentricaly , the structure will fail by yielding ?
yes, it bends under the eccentric moment and compresses under the axial load, and will yield at a load less than the buckling load about that axis. Failure by Euler buckling applies when the load is thru the centroid.
 
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