- #1

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## Homework Statement

The rope doesn't slide on the pulley, it's mass is negligible and it doesn't stretch .The pulley's moment of inertia is 0.00300 kg * m^2 with a radius of 10 cm. As the first mass goes down the rope's friction generates a moment of force of 0.150 N*m opposed to the angular speed of the pulley. Initially , both masses are motionless and m1 is at a height of 1.5m(h = 1.5m).

m

_{1}= 1.5 kg

m

_{2}= 0.8 kg

https://gyazo.com/074104f2af4ac27811136c21b4e1bcfb

## Homework Equations

τ = r*F

τ

_{resultant}= Σ(τ) = I* α

_{z}

F

_{resultant}= ma

α

_{z}= a

_{θ}/ r

-a

_{y1}= a

_{y2}

## The Attempt at a Solution

T

_{1}= -m

_{1}a

_{y1}+ m

_{1}g

T

_{2}= m

_{2}a

_{y2}+ m

_{2}g

-T

_{1}+ T

_{2}- 1.5 = I*a

_{y1}

replacing the values in the last equation with the first two equations and isolating a results 3.69 m/s

^{2}

the real solution is a

_{1}= -2.06 m/s

^{2}