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Homework Statement
The rope doesn't slide on the pulley, it's mass is negligible and it doesn't stretch .The pulley's moment of inertia is 0.00300 kg * m^2 with a radius of 10 cm. As the first mass goes down the rope's friction generates a moment of force of 0.150 N*m opposed to the angular speed of the pulley. Initially , both masses are motionless and m1 is at a height of 1.5m(h = 1.5m).
m_{1} = 1.5 kg
m_{2} = 0.8 kg
https://gyazo.com/074104f2af4ac27811136c21b4e1bcfb
Homework Equations
τ = r*F
τ_{resultant} = Σ(τ) = I* α_{z}
F_{resultant} = ma
α_{z} = a_{θ} / r
a_{y1} = a_{y2}
The Attempt at a Solution
T_{1} = m_{1}a_{y1} + m_{1}g
T_{2} = m_{2}a_{y2} + m_{2}g
T_{1} + T_{2}  1.5 = I*a_{y1}
replacing the values in the last equation with the first two equations and isolating a results 3.69 m/s^{2}
the real solution is a_{1} = 2.06 m/s^{2}
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