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## Homework Statement

So I'm in pchem right now and I haven't taken dif eq (it's not required, but I wish I had taken it now!)

I am asked to solve this differential equation:

y''+y'-2y=0

## Homework Equations

I know for a second order differential equation I can solve for the roots first. If there is one root then the solution will take the form y=c

_{1}e

^{rx}+c

_{2}xe

^{rx}

If there are two distinct roots I will get something like:

y=c

_{1}e

^{r1x}+c

_{2}e

^{r2x}

## The Attempt at a Solution

I tried to find the roots

r

^{2}+r-2=0

r= -2 and r=1

So I get:

y=c

_{1}e

^{-2x}+c

_{2}e

^{x}

I am pretty sure this is correct (I checked to see if I got zero if I did y''+y'-2y and I did), but

**is there a way to find c1 and c2?**