Second Order Linear Diff Eq

KleZMeR
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Quadratic Polynomial can't satisfy second order linear differential equation with constant coefficients... WHY?
and
if possible, how would I show this? Does it have to do with independence?
 
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ok

well i figured it out if anone cares
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
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