Semi-infinite slab, surface heating on a radius r=a; T=?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
7 replies · 3K views
leialee
Messages
10
Reaction score
0

Homework Statement


[/B]
We are heating a semi-infinite slab with a laser (radius of a stream is ##a##), which presents us with a steady surface heating (at ##z=0##), everywhere else on the surface the slab is isolated.
How does the temperature change with time?
Look at the limit cases: at ##t \to \infty##, at ##z=0##, in the direction of the laser beam, etc.

Homework Equations



So initialy the problem is 3D and we have cylindrical symmetry, and everything is the same for any given ##\phi##, so problem becomes 2D and the only coordinates relevant are ##r## and ##z##.

We have full diffusion equation
$$ D\nabla^2 T=\frac{\partial T}{\partial t}-\frac{q}{\rho c_p}$$

where ##q## is not a function of time, but it is Heaviside function of radius and delta function of ##z##; something like this: ##q(r,z)=H(a-r)\delta (z-0)## ??

Boundrary conditions are ##T(r\to \infty, z\to \infty, t)=0## and ##\partial T/ \partial z (z=0, a<r<\infty)=0##
Initial condition is ##T(r,z,t=0)=0##

I'm thinking to solve this with Green's functions; so that i take the solution for heating infinite space with a point source, but considering slab is semi-infinite I would multiply Green's function for infinite space by 2 (as in we have two sources each on one side of the surface so that there is no conducting over the surface??).

So I've got Greens function for infinite 3D object:
$$ G(\textbf{r}-\textbf{r}_0;t)=(4\pi Dt)^{-\frac{3}{2}} e^{-\frac{(\textbf{r}-\textbf{r}_0)^2}{4Dt}}$$
and its solution
$$T(\textbf{r},t)=\int_{-\infty}^{t+}dt_0 \int d^3r_0~G(\textbf{r}-\textbf{r}_0;t-t_0)\frac{q(\textbf{r}_0,t_0)}{\rho c_p}$$

I'm really not very sure how to take on this problem, so any discussion and comment would be most welcome.

The Attempt at a Solution

 
Physics news on Phys.org
Yeah, i checked that book out and its a bit to advanced for my knowleadge.
 
Okay, so i went to look into that book again; but i still don't understand. So maybe you would be so kind to explain to me some stuff from the chapter 8.2..
Like in 8.2, why does he take equation (1) for the temperature; where does that come from? Later on in (2) i would guess this goes by the fact that medium isn't finite, so all ##\lambda## are allowed.
Also, why does (4) satisfie (6), i don't see how.
 
leialee said:
Okay, so i went to look into that book again; but i still don't understand. So maybe you would be so kind to explain to me some stuff from the chapter 8.2..
Like in 8.2, why does he take equation (1) for the temperature; where does that come from? Later on in (2) i would guess this goes by the fact that medium isn't finite, so all ##\lambda## are allowed.
Also, why does (4) satisfie (6), i don't see how.
Ah I see, its the diffusion equation in cylindrical coordinates and for stacionary case.
 
Chestermiller said:
And yet you're using Green's functions.
Could you please explain to me at least the thought process, how Jaeger get the solution in 10.5 (4) ?