# Separable Differential Equation

## Homework Statement

Can someone please verify if I am solving this equation right.

## Homework Equations

Please refer to attachment.

## The Attempt at a Solution

Please refer to attachment.

#### Attachments

• IMG-20120124-00015.jpg
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## Answers and Replies

lanedance
Homework Helper
how about checking by differentiating
$$sin(y) = \frac{A}{\sqrt{x^2+1}}$$

$$\frac{d}{dx}sin(y) = \frac{d}{dx}\frac{A}{\sqrt{x^2+1}}$$

$$cos(y)\frac{dy}{dx} = 2A(x^2+1)^{-3/2}\frac{-1}{2}2x$$

$$cos(y) dy \frac{A}{\sqrt{x^2+1}} = -A(x^2+1)^{-3/2}2x.dx.sin(y)$$

$$cos(y)dy(x^2+1)= -sin(y)2x.dx$$

which is looking ok, you probably want to use your initial condition though