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Homework Help: Separable Differential Equation

  1. Jan 24, 2012 #1
    1. The problem statement, all variables and given/known data
    Can someone please verify if I am solving this equation right.

    2. Relevant equations
    Please refer to attachment.

    3. The attempt at a solution
    Please refer to attachment.

    Attached Files:

  2. jcsd
  3. Jan 24, 2012 #2


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    Homework Helper

    how about checking by differentiating
    [tex]sin(y) = \frac{A}{\sqrt{x^2+1}} [/tex]

    [tex]\frac{d}{dx}sin(y) = \frac{d}{dx}\frac{A}{\sqrt{x^2+1}} [/tex]

    [tex]cos(y)\frac{dy}{dx} = 2A(x^2+1)^{-3/2}\frac{-1}{2}2x [/tex]

    [tex]cos(y) dy \frac{A}{\sqrt{x^2+1}} = -A(x^2+1)^{-3/2}2x.dx.sin(y) [/tex]

    [tex]cos(y)dy(x^2+1)= -sin(y)2x.dx [/tex]

    which is looking ok, you probably want to use your initial condition though
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