Separately excited shunt generator

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SUMMARY

A separately excited shunt generator with a nameplate rating of 50kW, V(FL) = 125V, R(A) = 0.01 ohms, R(F) = 16 ohms, and an excitation voltage of 125 VDC was discussed. The full load armature current can be calculated using the formula I = P/V, resulting in 400A. The electromotive force (EMF) generated at full load is determined to be 125V, and the power dissipated in the shunt field is calculated as 100W. Additionally, the power dissipated in the armature is found to be 4W.

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  • Understanding of DC shunt generator principles
  • Basic electrical engineering concepts
  • Familiarity with circuit analysis techniques
  • Knowledge of power calculations in electrical systems
NEXT STEPS
  • Study the equivalent circuit of DC shunt generators
  • Learn about power dissipation in electrical components
  • Explore the characteristics of separately excited generators
  • Investigate the impact of armature resistance on generator performance
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Electronic engineering students, electrical engineers, and professionals involved in generator design and analysis will benefit from this discussion.

andrew7447
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I have a question that iv been stuck on for wile. I am in year 2, electronic engineering and I am having a little trouble with this.

A separately excited shunt generator has the following nameplate data, 50kW, V(FL) = 125, R(A) = .01 ohms, R(F) = 16 ohms and an excitation voltage of 125 VDC.

Calculate the full load armature current
The amount of EMT generated at full load
Power dissipated in the shunt field
Power dissipated in the armature
 
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Step 1 is to sketch the equivalent circuit and mark on it the data you are given. This shows that you at least understand what a DC shunt generator is.
 
thanks, i looked at it for a bit and redrew it, then realized how easy it actually was.
 

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