Seperable Differential Equations, Multiplicative Constant Confusion Help Clarify

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SUMMARY

The discussion centers on the confusion surrounding the multiplicative constant in separable differential equations, specifically in the context of integrating factors for linear ordinary differential equations (ODEs). The user, Dane, expresses a preference for solving problems through detailed proofs rather than relying on formulas, which can be easily forgotten. The conversation concludes that the multiplicative constant, such as 1/3, is absorbed into the arbitrary constant of integration, leading to equivalent solutions regardless of the approach taken.

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  • Understanding of separable differential equations
  • Familiarity with integrating factors in linear ODEs
  • Knowledge of the Boyce/Diprima textbook on differential equations
  • Basic concepts of arbitrary constants in integration
NEXT STEPS
  • Study the derivation of integrating factors for linear ODEs
  • Explore the concept of arbitrary constants in differential equations
  • Review examples of separable differential equations from the Boyce/Diprima textbook
  • Practice solving differential equations using both formulaic and proof-based methods
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Students and educators in mathematics, particularly those studying differential equations, as well as anyone seeking to deepen their understanding of integrating factors and the role of constants in solutions.

danerape
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I curiously never had a problem solving Seperable Equations in the Seperable Equations chapter of the Boyce/Diprima book. I am the kind of person who likes to do things the long way, and encountered a problem solving for an Integrating Factor(Linear ODE, NOT EXACT) the long proofy way. I tend not to use the (e^(INT)p(x)dx) formula. Formulas are too easy to forget.

In solving for the integrating factor, I came upon an easy seperable equation of course! I split this one up a little differently than usually, still correctly I think? I came up with an answer that differs from the formula approach.

Is the 1/3 absorbed by the constant or something?
PDF ATTACHED

Thanks,

Dane
 

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Yes you could say they are equal. I prefer to say they are the same thing - and if you wrote 15K3 instead of K1 it would the same thing. At this stage they are both arbitrary, in a sense they are not anything. When you make conform to an initial condition you will get the same result from either of them.
 

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